10(x^2+1)=101x

Solution for 10(x^2+1)=101x equation:

Simplifying
10(x2 + 1) = 101x

Reorder the terms:
10(1 + x2) = 101x
(1 * 10 + x2 * 10) = 101x
(10 + 10x2) = 101x

Solving
10 + 10x2 = 101x

Solving for variable 'x'.

Reorder the terms:
10 + -101x + 10x2 = 101x + -101x

Combine like terms: 101x + -101x = 0
10 + -101x + 10x2 = 0

Factor a trinomial.
(1 + -10x)(10 + -1x) = 0

Subproblem 1
Set the factor '(1 + -10x)' equal to zero and attempt to solve:

Simplifying
1 + -10x = 0

Solving
1 + -10x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -10x = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -10x = 0 + -1
-10x = 0 + -1

Combine like terms: 0 + -1 = -1
-10x = -1

Divide each side by '-10'.
x = 0.1

Simplifying
x = 0.1
Subproblem 2
Set the factor '(10 + -1x)' equal to zero and attempt to solve:

Simplifying
10 + -1x = 0

Solving
10 + -1x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-10' to each side of the equation.
10 + -10 + -1x = 0 + -10

Combine like terms: 10 + -10 = 0
0 + -1x = 0 + -10
-1x = 0 + -10

Combine like terms: 0 + -10 = -10
-1x = -10

Divide each side by '-1'.
x = 10

Simplifying
x = 10
Solution
x = {0.1, 10}